Tần số Span là 2 Mhz, có 10 ô đơn vị nên mỗi ô đơn vị có giá trị 200 khz. Suy ra 2 thành phần tần số có đỉnh tại 2 marker có tần số lần lượt là 2.4002 và 2.4006 (giống với tính toán lý thuyết)
Span frequency is 2 Mhz, there are 10 unit cells so each unit cell has a value of 200 kHz. Deduce that the 2 frequency components have peaks at 2 markers with frequencies of 2.4002 and 2.4006 respectively (similar to theoretical calculations).
The frequency span is 2 Mhz, with 10 units, so the value of each unit is 200 khz. The peak frequency components of the two signals are 2.4002 and 2.4006, respectively (consistent with theoretical calculations)
The frequency is 2 MHz and there are 10 unit cells, so the value of each unit cell is 200 kHz. Two frequency components peak at two marks, and the frequency is 2. 4002 and 2. 4006 (same as theoretical calculation)